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(4)/(5)th part of a tank is filled with ...

`(4)/(5)`th part of a tank is filled with oil. After taking out 42 litres of oll the tank is `(3)/(4)`th part full. What is the capacity (in litres) of the tank?

A

420

B

630

C

840

D

1680

Text Solution

AI Generated Solution

The correct Answer is:
To find the capacity of the tank, let's break down the problem step by step. ### Step 1: Define the capacity of the tank Let the capacity of the tank be \( x \) liters. ### Step 2: Determine the initial amount of oil in the tank According to the problem, \( \frac{4}{5} \) of the tank is filled with oil. Therefore, the amount of oil initially in the tank is: \[ \text{Initial oil} = \frac{4}{5}x \] ### Step 3: Calculate the amount of oil after taking out 42 liters After taking out 42 liters of oil, the tank is now \( \frac{3}{4} \) full. Thus, the amount of oil left in the tank is: \[ \text{Remaining oil} = \frac{3}{4}x \] ### Step 4: Set up the equation From the information given, we can set up the following equation: \[ \frac{4}{5}x - 42 = \frac{3}{4}x \] ### Step 5: Solve the equation To solve for \( x \), we first eliminate the fractions by finding a common denominator. The least common multiple of 5 and 4 is 20. We can multiply the entire equation by 20 to eliminate the fractions: \[ 20 \left(\frac{4}{5}x\right) - 20(42) = 20 \left(\frac{3}{4}x\right) \] This simplifies to: \[ 16x - 840 = 15x \] ### Step 6: Rearrange the equation Now, we can rearrange the equation to isolate \( x \): \[ 16x - 15x = 840 \] \[ x = 840 \] ### Step 7: Conclusion The capacity of the tank is \( 840 \) liters. ---
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