A train is running at a speed of 116km/hr. The distance covered by the train in metres in 18 seconds is

Options

A. 900metre
B. 1160 metre
C. 508 metre
D. 580 metre

Answer

To solve the problem, we need to calculate the distance covered by a train running at a speed of 116 km/hr in 18 seconds. Here’s a step-by-step solution:

### Step 1: Convert the speed from km/hr to m/s
To convert kilometers per hour (km/hr) to meters per second (m/s), we use the conversion factor:
\[ 1 \text{ km/hr} = \frac{1000 \text{ meters}}{3600 \text{ seconds}} = \frac{1}{3.6} \text{ m/s} \]
Thus, to convert 116 km/hr to m/s:
\[ 116 \text{ km/hr} = 116 \times \frac{1}{3.6} \text{ m/s} \]
Calculating this gives:
\[ 116 \div 3.6 \approx 32.222 \text{ m/s} \]

### Step 2: Use the formula for distance
The formula for distance is given by:
\[ \text{Distance} = \text{Speed} \times \text{Time} \]
In this case, the speed is approximately 32.222 m/s and the time is 18 seconds.

### Step 3: Calculate the distance
Now, we can calculate the distance:
\[ \text{Distance} = 32.222 \text{ m/s} \times 18 \text{ s} \]
Calculating this gives:
\[ \text{Distance} \approx 581.996 \text{ meters} \]

### Step 4: Round the distance
Since we are typically interested in whole numbers for distance, we can round this to:
\[ \text{Distance} \approx 582 \text{ meters} \]

### Final Answer
The distance covered by the train in 18 seconds is approximately **582 meters**.

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