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A train starts moving from a place X at ...

A train starts moving from a place X at 7:00 a.m. and arrives at another place Y at 1:00 pm on the same day. If the speed of the trains 15m/s, then what will be the distance (in km) covered by the train?

A

324

B

375

C

390

D

345

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to determine the distance covered by the train using the formula for distance, which is: \[ \text{Distance} = \text{Speed} \times \text{Time} \] ### Step-by-Step Solution: **Step 1: Calculate the total time taken by the train.** The train starts at 7:00 a.m. and arrives at 1:00 p.m. To find the total time taken, we calculate the difference between these two times. - From 7:00 a.m. to 1:00 p.m. is 6 hours. **Step 2: Convert the speed from meters per second to kilometers per hour.** The speed of the train is given as 15 m/s. To convert this speed into kilometers per hour (km/h), we use the conversion factor: \[ 1 \text{ m/s} = 3.6 \text{ km/h} \] So, \[ \text{Speed in km/h} = 15 \text{ m/s} \times 3.6 \text{ km/h per m/s} = 54 \text{ km/h} \] **Step 3: Calculate the distance using the formula.** Now that we have the speed in km/h and the time in hours, we can calculate the distance. Using the formula: \[ \text{Distance} = \text{Speed} \times \text{Time} \] Substituting the values we have: \[ \text{Distance} = 54 \text{ km/h} \times 6 \text{ hours} = 324 \text{ km} \] ### Final Answer: The distance covered by the train is **324 km**. ---
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