A train travelling at a speed of 55km/hr travels from place X to place Y in 4 hours. If its speed is increased by 5km/hr., then the time of journey is reduced by

Options

A. 25 minutes
B. 35 minutes
C. 20 minutes
D. 30 minutes

Answer

To solve the problem step by step, we will follow these calculations:

### Step 1: Calculate the distance traveled by the train
The formula for distance is:
\[ \text{Distance} = \text{Speed} \times \text{Time} \]

Given:
- Speed = 55 km/hr
- Time = 4 hours

So, the distance traveled from place X to place Y is:
\[ \text{Distance} = 55 \, \text{km/hr} \times 4 \, \text{hours} = 220 \, \text{km} \]

### Step 2: Calculate the new speed of the train
If the speed is increased by 5 km/hr, the new speed will be:
\[ \text{New Speed} = 55 \, \text{km/hr} + 5 \, \text{km/hr} = 60 \, \text{km/hr} \]

### Step 3: Calculate the new time taken to travel the same distance
Using the distance we calculated in Step 1 (220 km) and the new speed (60 km/hr), we can find the new time:
\[ \text{Time} = \frac{\text{Distance}}{\text{Speed}} \]
\[ \text{New Time} = \frac{220 \, \text{km}}{60 \, \text{km/hr}} \]

Calculating this gives:
\[ \text{New Time} = \frac{220}{60} = \frac{11}{3} \, \text{hours} \]
To convert this into minutes, we multiply by 60:
\[ \text{New Time in minutes} = \frac{11}{3} \times 60 = 220 \, \text{minutes} \]

### Step 4: Calculate the reduction in time
The original time was 4 hours, which is:
\[ 4 \, \text{hours} = 240 \, \text{minutes} \]

Now, we find the reduction in time:
\[ \text{Reduction in Time} = \text{Original Time} - \text{New Time} \]
\[ \text{Reduction in Time} = 240 \, \text{minutes} - 220 \, \text{minutes} = 20 \, \text{minutes} \]

### Final Answer
The time of the journey is reduced by **20 minutes**.

---