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Two trains are moving in the same direction at speeds of 54km/h and 92km/h, their lengths are 400m and 360m respectively. What is the time taken (in seconds) by faster train to cross the slower train?

A

A)60

B

B)72

C

C)81

D

D)90

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of how long it takes for the faster train to cross the slower train, we can follow these steps: ### Step 1: Determine the lengths of the trains - The length of the first train (slower train) = 400 meters - The length of the second train (faster train) = 360 meters ### Step 2: Calculate the total distance to be covered - Total distance = Length of the slower train + Length of the faster train - Total distance = 400 m + 360 m = 760 m ### Step 3: Determine the speeds of the trains - Speed of the slower train = 54 km/h - Speed of the faster train = 92 km/h ### Step 4: Calculate the relative speed - Since both trains are moving in the same direction, the relative speed is the difference in their speeds. - Relative speed = Speed of the faster train - Speed of the slower train - Relative speed = 92 km/h - 54 km/h = 38 km/h ### Step 5: Convert the relative speed from km/h to m/s - To convert km/h to m/s, we use the conversion factor: 1 km/h = 5/18 m/s. - Relative speed in m/s = 38 km/h × (5/18) = (38 × 5) / 18 = 190 / 18 m/s - Simplifying gives us approximately 10.56 m/s. ### Step 6: Calculate the time taken to cross the slower train - Time = Distance / Speed - Time = Total distance / Relative speed - Time = 760 m / (190 / 18) m/s - Time = 760 m × (18 / 190) s - Time = (760 × 18) / 190 seconds ### Step 7: Simplify the calculation - Time = 13680 / 190 seconds - Time = 72 seconds ### Final Answer The time taken by the faster train to cross the slower train is **72 seconds**. ---
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