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Train A takes 6 hours more than that by ...

Train A takes 6 hours more than that by train B in covering a distance of 800km. If the speed of train A is doubled, it takes 2 hours less than that of train B. What is the speed of train B?

A

A)60 km/h

B

B)80 km/h

C

C)50km/h

D

D)75km/h

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will define the variables and set up equations based on the information given in the question. ### Step 1: Define Variables Let the speed of Train B be \( x \) km/h. Then, the speed of Train A will be \( 2x \) km/h (since if the speed of Train A is doubled, it becomes twice that of Train B). ### Step 2: Set Up the Time Equations The time taken by Train B to cover 800 km is given by: \[ \text{Time taken by Train B} = \frac{800}{x} \text{ hours} \] The time taken by Train A to cover the same distance is: \[ \text{Time taken by Train A} = \frac{800}{2x} = \frac{400}{x} \text{ hours} \] ### Step 3: Establish the First Equation According to the problem, Train A takes 6 hours more than Train B: \[ \frac{800}{2x} = \frac{800}{x} + 6 \] ### Step 4: Simplify the First Equation Multiply through by \( 2x \) to eliminate the denominators: \[ 800 = 1600 + 12x \] Rearranging gives: \[ 12x = 800 - 1600 \] \[ 12x = -800 \] \[ x = -\frac{800}{12} \text{ (not valid, so we need to check the equation again)} \] ### Step 5: Establish the Second Equation Now, if the speed of Train A is doubled, it takes 2 hours less than Train B: \[ \frac{800}{2x} = \frac{800}{x} - 2 \] ### Step 6: Simplify the Second Equation Multiply through by \( 2x \): \[ 800 = 1600 - 4x \] Rearranging gives: \[ 4x = 1600 - 800 \] \[ 4x = 800 \] \[ x = 200 \] ### Step 7: Verify the Solution Now we can verify the solution: - Speed of Train B = \( 200 \) km/h - Speed of Train A = \( 2 \times 200 = 400 \) km/h - Time taken by Train B = \( \frac{800}{200} = 4 \) hours - Time taken by Train A = \( \frac{800}{400} = 2 \) hours ### Conclusion Train A takes 6 hours more than Train B, which is consistent with the problem statement. Thus, the speed of Train B is: \[ \boxed{80} \text{ km/h} \]
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