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P and Q starting simultaneously from two different places proceed towards each other at a speed of 20 km/hour and 30 km/hour respectively. By the time they meet each other. Q has covered 36km more than that of P. The distance (in km) between the two places is

A

144

B

162

C

180

D

108

Text Solution

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The correct Answer is:
To solve the problem, we will follow these steps: ### Step 1: Define the variables Let: - Speed of P = 20 km/h - Speed of Q = 30 km/h - Time taken to meet = T hours - Distance covered by P = Distance covered by Q - 36 km ### Step 2: Write the equations for distances The distance covered by P can be expressed as: \[ \text{Distance covered by P} = 20 \times T \] The distance covered by Q can be expressed as: \[ \text{Distance covered by Q} = 30 \times T \] ### Step 3: Set up the equation based on the problem statement According to the problem, Q has covered 36 km more than P: \[ 30T = 20T + 36 \] ### Step 4: Solve the equation for T Rearranging the equation: \[ 30T - 20T = 36 \] \[ 10T = 36 \] \[ T = \frac{36}{10} = 3.6 \text{ hours} \] ### Step 5: Calculate the total distance between P and Q The total distance between the two places is the sum of the distances covered by P and Q: \[ \text{Total Distance} = \text{Distance covered by P} + \text{Distance covered by Q} \] \[ \text{Total Distance} = 20T + 30T = 50T \] Substituting T: \[ \text{Total Distance} = 50 \times 3.6 = 180 \text{ km} \] ### Final Answer The distance between the two places is **180 km**. ---
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