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A train of length 100 metre crosses anot...

A train of length 100 metre crosses another train of length 150 metre, running on a parallel track in the opposite direction in 9 seconds. If the speed of train having length 150 metre is 40 km/hr, then what is the speed (in km/hr) of the other train?

A

30

B

48

C

50

D

60

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will follow these steps: ### Step 1: Understand the Problem We have two trains: - Train A: Length = 100 meters - Train B: Length = 150 meters - Speed of Train B = 40 km/hr - Time taken to cross each other = 9 seconds We need to find the speed of Train A. ### Step 2: Calculate the Total Distance Covered When two trains cross each other, the total distance covered is the sum of their lengths. - Total distance = Length of Train A + Length of Train B - Total distance = 100 m + 150 m = 250 m ### Step 3: Convert the Speed of Train B to m/s Since we will be using the time in seconds, we should convert the speed of Train B from km/hr to m/s. - Speed in m/s = Speed in km/hr × (1000 m / 3600 s) - Speed of Train B = 40 km/hr × (1000 / 3600) = 40 × (5/18) = 11.11 m/s (approximately) ### Step 4: Calculate the Relative Speed of Both Trains The relative speed of two trains moving in opposite directions is the sum of their speeds. Let the speed of Train A be \( s_1 \) (in m/s). - Relative speed = Speed of Train A + Speed of Train B - Relative speed = \( s_1 + 11.11 \) m/s ### Step 5: Use the Time to Cross Each Other We know the time taken to cross each other is 9 seconds. Using the formula: - Distance = Speed × Time - 250 m = (Relative speed) × Time - 250 = (s_1 + 11.11) × 9 ### Step 6: Solve for \( s_1 \) Now, we can solve for \( s_1 \): - 250 = 9(s_1 + 11.11) - 250 = 9s_1 + 100 - 9s_1 = 250 - 100 - 9s_1 = 150 - \( s_1 = \frac{150}{9} \) - \( s_1 \approx 16.67 \) m/s ### Step 7: Convert \( s_1 \) to km/hr To convert the speed of Train A from m/s to km/hr: - Speed in km/hr = Speed in m/s × (3600 s / 1000 m) - Speed of Train A = 16.67 m/s × (3600 / 1000) = 16.67 × 3.6 ≈ 60 km/hr ### Final Answer The speed of the other train (Train A) is approximately **60 km/hr**. ---
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