Home
Class 14
MATHS
A moving train crosses a man standing on...

A moving train crosses a man standing on a platform and a bridge 300 metres long in 10 seconds and 25 seconds respectively. What will be the time taken by the train to cross a platform 200 metres long?

A

`16(2)/(3)` seconds

B

18 seconds

C

20 seconds

D

22 seconds

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to determine the time taken by the train to cross a platform that is 200 meters long. We will first find the length of the train and its speed, then use that information to calculate the time taken to cross the 200-meter platform. ### Step 1: Find the speed of the train when it crosses the man When the train crosses a man standing on the platform, it covers its own length (let's denote the length of the train as \( L \)) in 10 seconds. - Speed of the train \( v = \frac{L}{10} \) meters per second. ### Step 2: Find the speed of the train when it crosses the bridge When the train crosses a bridge that is 300 meters long, it covers the distance equal to its length plus the length of the bridge in 25 seconds. - Distance covered = \( L + 300 \) - Speed of the train \( v = \frac{L + 300}{25} \) meters per second. ### Step 3: Set the two expressions for speed equal to each other Since both expressions represent the speed of the train, we can set them equal to each other: \[ \frac{L}{10} = \frac{L + 300}{25} \] ### Step 4: Cross-multiply to solve for \( L \) Cross-multiplying gives us: \[ 25L = 10(L + 300) \] Expanding the right side: \[ 25L = 10L + 3000 \] ### Step 5: Rearrange the equation to isolate \( L \) Subtract \( 10L \) from both sides: \[ 25L - 10L = 3000 \] \[ 15L = 3000 \] ### Step 6: Solve for \( L \) Dividing both sides by 15 gives: \[ L = \frac{3000}{15} = 200 \text{ meters} \] ### Step 7: Find the speed of the train Now that we know the length of the train is 200 meters, we can find the speed of the train using the first equation: \[ v = \frac{L}{10} = \frac{200}{10} = 20 \text{ meters per second} \] ### Step 8: Calculate the time taken to cross a 200-meter long platform When the train crosses a platform that is 200 meters long, it has to cover its own length plus the length of the platform: - Total distance to cover = \( L + 200 = 200 + 200 = 400 \) meters. Using the speed we found: \[ \text{Time} = \frac{\text{Distance}}{\text{Speed}} = \frac{400}{20} = 20 \text{ seconds} \] ### Final Answer The time taken by the train to cross a platform 200 meters long is **20 seconds**. ---
Promotional Banner

Topper's Solved these Questions

  • TIME AND DISTANCE

    KIRAN PUBLICATION|Exercise Type -XI|74 Videos
  • TIME AND DISTANCE

    KIRAN PUBLICATION|Exercise Type -IX|19 Videos
  • STATISTICS AND DATA INTERPRETATION

    KIRAN PUBLICATION|Exercise TYPE-VIII|8 Videos
  • TIME AND WORK

    KIRAN PUBLICATION|Exercise TEST YOURSELF|25 Videos

Similar Questions

Explore conceptually related problems

A train 280m long is moving at a speed of 60kmph. What is the time taken by the train to cross a platform 220 long

A 180 - metre long train crosses a man standing on the platform in 6 seconds. What is the speed of the train?