The distance between place A and B is 999km. An express train leaves place A at 6am and runs at a speed of 55.5km/hr. The train stops on the way for 1 hour 20 minutes. It reaches B at

Options

A. 1.20 am
B. 12pm
C. 6pm
D. 11pm

Answer

To solve the problem, we need to calculate the total time taken by the express train to travel from place A to place B, including the time spent on stops.

### Step-by-Step Solution:

1. **Calculate the time taken to travel the distance without stops:**
- The formula to calculate time is:
\[ \text{Time} = \frac{\text{Distance}}{\text{Speed}} \]
- Here, the distance is 999 km and the speed is 55.5 km/hr.
- So, the time taken to travel without stops is:
\[ \text{Time} = \frac{999 \text{ km}}{55.5 \text{ km/hr}} \approx 18.0 \text{ hours} \]

2. **Convert the stop time into hours:**
- The train stops for 1 hour and 20 minutes.
- To convert this into hours:
\[ 1 \text{ hour} + \frac{20 \text{ minutes}}{60} = 1 + \frac{1}{3} = \frac{4}{3} \text{ hours} \approx 1.33 \text{ hours} \]

3. **Calculate the total time taken for the journey:**
- Total time = Time taken to travel + Stop time
- Total time = 18.0 hours + 1.33 hours = 19.33 hours

4. **Determine the arrival time:**
- The train leaves at 6:00 AM.
- To find the arrival time, we add the total travel time to the departure time.
- 19.33 hours is equivalent to 19 hours and 20 minutes.
- Adding this to 6:00 AM:
- 6:00 AM + 19 hours = 1:00 AM (next day)
- Then add 20 minutes: 1:00 AM + 20 minutes = 1:20 AM

Thus, the train reaches place B at **1:20 AM** the next day.