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The current of a stream runs at the r...

The current of a stream runs at the rate of 4km an hour . A boat goes 6 km and comes back to the starting point in 2 hours .The speed of the boat in still water is

A

6 km/ hr

B

8 km/hr

C

7.5 km/hr

D

6.8 km/hr

Text Solution

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The correct Answer is:
To solve the problem of finding the speed of a boat in still water given the current of a stream and the time taken for a round trip, we can follow these steps: ### Step 1: Define Variables Let the speed of the boat in still water be \( x \) km/h. The speed of the stream is given as 4 km/h. ### Step 2: Determine Effective Speeds When the boat is moving downstream (going with the current), its effective speed is: \[ \text{Speed downstream} = x + 4 \text{ km/h} \] When the boat is moving upstream (against the current), its effective speed is: \[ \text{Speed upstream} = x - 4 \text{ km/h} \] ### Step 3: Calculate Time for Each Leg of the Journey The distance for each leg of the journey is 6 km. The time taken to go downstream is: \[ \text{Time downstream} = \frac{6}{x + 4} \] The time taken to come back upstream is: \[ \text{Time upstream} = \frac{6}{x - 4} \] ### Step 4: Set Up the Equation According to the problem, the total time for the round trip is 2 hours. Therefore, we can set up the equation: \[ \frac{6}{x + 4} + \frac{6}{x - 4} = 2 \] ### Step 5: Clear the Fractions To eliminate the fractions, we can multiply through by the common denominator, which is \((x + 4)(x - 4)\): \[ 6(x - 4) + 6(x + 4) = 2(x + 4)(x - 4) \] ### Step 6: Expand and Simplify Expanding both sides gives: \[ 6x - 24 + 6x + 24 = 2(x^2 - 16) \] This simplifies to: \[ 12x = 2x^2 - 32 \] ### Step 7: Rearrange into Standard Form Rearranging the equation gives: \[ 2x^2 - 12x - 32 = 0 \] Dividing through by 2 simplifies it to: \[ x^2 - 6x - 16 = 0 \] ### Step 8: Factor the Quadratic Equation To factor the quadratic, we look for two numbers that multiply to -16 and add to -6. The numbers -8 and 2 work: \[ (x - 8)(x + 2) = 0 \] ### Step 9: Solve for \( x \) Setting each factor to zero gives: \[ x - 8 = 0 \quad \Rightarrow \quad x = 8 \] \[ x + 2 = 0 \quad \Rightarrow \quad x = -2 \] Since speed cannot be negative, we discard \( x = -2 \). ### Step 10: Conclusion Thus, the speed of the boat in still water is: \[ \boxed{8} \text{ km/h} \]
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