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The sum of series 1+2+3+4+…………+998+999+1...

The sum of series `1+2+3+4+…………+998+999+1000` is

A

5050

B

500500

C

550000

D

55000

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AI Generated Solution

The correct Answer is:
To find the sum of the series \(1 + 2 + 3 + 4 + \ldots + 998 + 999 + 1000\), we can use the formula for the sum of the first \(n\) natural numbers, which is given by: \[ S_n = \frac{n(n + 1)}{2} \] ### Step-by-Step Solution: 1. **Identify \(n\)**: In this case, we are summing the first 1000 natural numbers, so \(n = 1000\). 2. **Apply the formula**: Substitute \(n\) into the formula: \[ S_{1000} = \frac{1000(1000 + 1)}{2} \] 3. **Calculate \(1000 + 1\)**: \[ 1000 + 1 = 1001 \] 4. **Multiply \(1000\) and \(1001\)**: \[ 1000 \times 1001 = 1001000 \] 5. **Divide by \(2\)**: \[ S_{1000} = \frac{1001000}{2} = 500500 \] Thus, the sum of the series \(1 + 2 + 3 + 4 + \ldots + 998 + 999 + 1000\) is \(500500\). ### Final Answer: \[ \text{The sum of the series is } 500500. \] ---
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