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Given that 1^(2) + 2^(2) + 3^(2) + ... ...

Given that ` 1^(2) + 2^(2) + 3^(2) + ... + 20^(2) = 2870`, the value of ` (2^(2) + 4^(2) + 6^(2) + ... + 40^(2))` is :

A

11480

B

5740

C

28700

D

2870

Text Solution

Verified by Experts

The correct Answer is:
A
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