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If 1^2+2^2+3^2+.....+x^2=((x)(x+1)(2x+1)...

If `1^2+2^2+3^2+.....+x^2=((x)(x+1)(2x+1))/6`, then the value of `1^2+3^2+5^2+.......+19^2` is equal to:

A

1330

B

2100

C

2485

D

2500

Text Solution

Verified by Experts

The correct Answer is:
A
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