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Find the area of the smaller region boun...

Find the area of the smaller region bounded by the (ii) `x^2/16+y^2/9=1` and the straight line 3x+4y=12.

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The correct Answer is:
`3(pi+2)` sq. units.
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ACCURATE PUBLICATION-APPLICATIONS OF INTEGRALS-QUESTIONS CARRYING 2 MARKS
  1. Find the area of the smaller region bounded by the (ii) x^2/16+y^2/9=1...

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  2. Find the area of region bounded by y^(2)=4x,x=1,x=4 and x axis in the ...

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  3. Draw a graph of x^(2)/16+y^(2)/9=1 and evaluate area bounded by it.

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  4. Find the area of the region in the first quadrant enclosed by the x-ax...

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  5. Using integration, find the area of the region in the first quadrant e...

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  6. Using integration, find the area of the region bounded by the line x -...

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  7. Find the area of the region enclosed by the curve y^(2)=4x and the lin...

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  8. Using integration, find the area of the region bounded by the line y -...

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  9. Find the area of the region bounded by the curve x^(2)=4y and the stra...

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  10. Find the area of the region included between the parabola y^(2)=x and ...

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  11. Draw the rough sketch and find the area of the region: (i){(x,y):x^2 <...

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  12. Using integration find the area of region bounded by the triangle wher...

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  13. Find the area of the region {(x,y):x^(2)+y^(2) le 1 le x+y}.

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  14. Using integration, find the area of the region: {(x,y): |x-1|leylesqrt...

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  15. Find the area of the region: (ii) {(x,y):x^2leyle|x|}.

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  16. Find the area of the region bounded by the parabola y = x^2 and y = |x...

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  17. Using integration, find the area of the region bounded by the followin...

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  18. Draw the graph of y=abs(x+1) and using integration, find the area belo...

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