The resistance of a 0.5 M solution of an electrolyte in a conductivity 'cell was found to be 25 ohm. Calculate the molar conductivity of the solution, if the electrodes in the cell are 1.6 cm apart and have an area of `3*2cm^(2)`.

Explanation

Given R= 25ohm, l= 1.6cm , a= `3.2 cm^(2)`
Conductivity is `K = C xx (l)/(a)`
`K= (1)/(R ) xx (l)/(a) = (1)/(25) xx (16)/(32) = (1)/(50) "ohm"^(-1) cm^(-1)`
`Lamda_(eq)= (K xx 1000)/(N)= (1)/(50)xx (1000)/(0.5) =40 "Ohm"^(-1) cm^(2) eq^(-1)`