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Calculate two third life of a first orde...

Calculate two third life of a first order reaction having `k=5.48xx 10^(-14) s^-1`.

Text Solution

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Let Initial Conc. `[A]_0 = a `
`[A] = a - (2a)/3 = a/3`
First Order Equation `t = (2.303)/(k) "log" ([A]_0)/([A])`
So, `t = (2.303)/(k) "log" a/a xx 3`
`t_(2//3) = (2.303)/(5.48 xx 10^(-14)) "log 3 " [because log 3 = 0.4771]`
`= 2.01 xx 10^(13)s`
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