The reaction `2 A + B + C to D + 2 E` is of first order with respect to A and of second order with respect to B and is of zero order with respect to C
Write down the rate law for the reaction

Explanation

The reaction is `2A +B+C to D + 2E`
Given
(i) Since, this is first order w.r.t. A, second order w. r. t. B, and 0 order w.r. t. C.
Rate law = `k[A] [B]^2[C]^0`
Rate, `R = K[A] [B]^2`
(ii) Now rate, `R. = k[2A] [2B]^2 = 8k[A] [B]^2 = 8k `
`therefore` Rate becomes 8 times.