A first order reaction is 20 % complete in 10 minutes. Calculate
Specific rate constant of the reaction

Explanation

(i) At time, `t = 10 "min", [A] =0.8 [A]_0`
`therefore 0.8 [A]_0 = [A]_0 e^(-10k)`
`impliesk = 0.022 "min"^(-1)`
(ii) When 75% reaction is completed, `[A] = 1/4 [A]_0`
`therefore 1/4 [A]_0 =[A]_0 e^(0.022 t)`
`implies 6 = 63.01 ` min