For the reaction :
`2N_2O_5 rarr 4NO_2+O_2`
the rate of reaction measured as `(Delta[NO_2])/(Deltat)` was found to be `4 xx 10^(-3)" mol L"^(-1)` is `s^(-1)`. Calculate the rate of reaction, expressed in terms of `N_2O_5`

Explanation

We know, `-1/2 (d[N_2O_5])/(dt) = 1/2 (d[NO_2])/(dt)`
`-1/2 (d[N_2O_5])/(dt) = 1/4 xx 10^(-3)`
`-1/2 (d[N_2O_5])/(dt) = 1 xx 10^(-3) "mol lit"^(-1) sec`