The half life period for a reaction of first order is `2.31xx10^3` min. How long will it take for `1/5^(th)` of the reactants to be left behind.

Explanation

`t_(1/2) = (0.693)/k`
`k = (0.693)/(2.31 xx 10^3) implies 0.3 xx 10^(-3)`
`t = (2.303)/(0.3 xx 10^(-3)) " log 5"`
` 5.369 xx 10^(-3)` min