For a chemical reaction temperature ranges from 650 K to 750 K with rate constant 2.15 to 2.39. Find Activation Energy.

Explanation

`"log" (k_2)/(k_1) = (2E_a)/(19.17) [(T_2 - T_1)/(T_2T_1)]`
`"log" (2.39)/(2.15) = (E-a)/(19.17) [(700 - 650)/(455000)]`
`E_(a) = (0.0459 xx 19.17 xx 45500)/(5)`
`E_a = 79.968 kJ mol^(-1)`