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60% of a first order reaction was comple...

60% of a first order reaction was completed in 60 minutes. When was it half completed ?

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`k = (2.303)/60" log "100/40`
`= (2.303 xx 0.398)/(60)`
`= 0.0158 sec^(-1)`
`t= (2.303)/(0.0153) log 2 `
`t = 45.4 `min.
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