A first order reaction is 20% complete in 20 minuts. Calculate the time it will take the reaction to complete 80%.

Explanation

`(k = (2.303)/(t) "log" ([A]_0)/([A]))/(=(2.303)/20 "log" 100/80)`
`= (2.303)/(80) xx 0.69697 `
`k = 0.0112 "min"^(-1)`
`t = (2.303)/(k) "log" ([A]_0)/([A])`
`t= (2.303)/(0.0112)"log" 100/20`
`t = (2.303)/(0.0112) "log 5"`
`t = 144 "min"`