Calculate two third life of first order reaction having `K = 5.48 xx 10^(-14)s^(-1)`.

Explanation

Let Initial Cone. `[A]_0 = a`
`[A] = a - (2a)/3 = a/3`
First Order Equation `t = (2.303)/k log"" ([A]_0)/([A])`
So, `t = (2.303)/k log"" (a)/a xx 3`
`t_(2//3) = (2.303)/(5.48 xx 10^(-14)) log 3 [ :. log 3 = 0.4771]`
` = 2.01 xx 10^3s`