Compare and explain bond angles of
`H_2O` and `H_2S`

Explanation

Bond angle of `H_(2)O` is larger because oxygen is more electronegative than sulphur therefore bond pair electron of O-H bond will be closer to oxygen and bond-pair bond-pair repulsion between bond pairs of two O-H bonds.
Bond angle in `H_(2)O` (`104.5^(@)`) is higher than the bond angle of `H_(2)S` (`92.1^(@)`). The difference is due to :

(A) O is diatomic and S is tetra-atomic.
(B) Difference in electronegativity of Sand O.
(C) Difference in oxidation states of S and O.
(D) Difference in shapes of hybrid orbitals of S and O.