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The rate constant for a first order reac...

The rate constant for a first order reaction Is 90 `s^-1` .How much time will it take to reduce the concentration of the reactant to `1/20^(th)` of its Initial value ?

Text Solution

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For the first order Reaction
`t=(2.303)/(k) log""([A_(0)])/([A])`
`k=90s^(-1), [A]=([A_(0)])/(20)` So `t=(2.303)/(90)xx log""([A_(0)])/([A_(0)]//20)`
t = 0.033 sec
`t=3.3 xx 10^(-2)` s.
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