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Rate constant for a first order reaction...

Rate constant for a first order reaction is `60 s ^(-1) . ` How much time will it take to reduce the concentration of the reaction on `(1)/(10)` th of its initial value.

Text Solution

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`t=(2.303)/(K)log ""([A]_(0))/([A])" "`(First Order Equation)
`k=60 S^(-1)" "[A]=([A]_(0))/(10)" "[log_(10)=1]`
`t=(2.303)/(60)log ""([A]_(0)10)/([A]_(0))`
`t=0.038`
`t=3.8xx10^(-2) s`
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