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At 298 K the vapour pressure of pure b...

At 298 K the vapour pressure of pure benzene `C_(6) H_(6) ` is 0.256 bar and vapour pressure of pure toluene, `C_(6)H_(8) ` is 0.925 bar. If the mole fraction of benzene in solution is 0 . 40 , find the total vapour pressure of solution. Also find the mole fraction of toluene in vapour phase

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(mole fraction of benzene) `x_B = 0.40" "p_B^@` =0.256 bar, `p_T^@` =0.925 bar
(mole fraction of Toluene) `x_T= 1-x_B`
= 1-0.4 = 0.6
(Total Vapour Pressure of solution) `P_B = p_B + p_T`
`= p_B^@ x_B + p_T^@ x_T`
`= 0.256 xx 0.40 +0.925 xx 0.6`
= 0.6574 bar
Mole fraction of toluene in vapour phase.
`y_T=(P_T)/(P_("solution"))=(P_T^@ x_T)/(P_("solution"))=(0.555)/(0.6574) = 0.844`
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