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Calculate two third life of first order ...

Calculate two third life of first order reaction having `K = 5.48 xx 10^(-14)s^(-1)`.

Text Solution

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Let Initial Conc. `[A]_(0) = a`
`[A] = a - (2a)/(3)=a/3`
First Order Equation `t=(2.303)/(k) log"" ([A_(0)])/([A])`
So, `t=(2.303)/(t) log"" a/a xx 3`
`t_(2//3)=(2.303)/(5.48xx10^(-14))log""3" "[:. log"" 3 = 0.4771]`
`=2.01xx10^(13) s`
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