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Give cell is {:([Ni|Ni^(2+) ||Cu^(2+)|Cu...

Give cell is `{:([Ni|Ni^(2+) ||Cu^(2+)|Cu]),(" (0.01m) (0.1m)"):}`
`E_("cell")= 0.59V`
Write Nernst equation and find `E_("N_(i)^(2+)//N_(l))^(@)` of cell. (At anode) `E_(Cu^(2+)//Cu)^(@)= 0.39V`

Text Solution

Verified by Experts


`E_("cell")=(E_((Cu^(2+)|Cu))^@-E_((Ni^(2+)|Ni))^@)-(0.059)/(2)log""((0.01))/((0.1))" "`[Nernst equation]
`0.59 V=(0.39V-E_((Ni^(2+)|Ni))^@)-(0.059)/(2)log""10^(-1)`
`0.59-0.39= -E_((Ni^(2+)|Ni))^@+0.0295`
`0.2= -E_((Ni^(2+)|Ni))^@+0.0295`
`E_((Ni^(2+)|Ni))^@=0.0295-0.2`
`E_((Ni^(2+)|Ni))^@= -0.1705 V`
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