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Electrons of mass m with de - Broglie wa...

Electrons of mass m with de - Broglie wavelength , `lambda`fall on the target in an X-ray tube . The cutoff wavelength`(lambda_0)`of the emitted X-ray is:

A

`lambda_0=(2m^2c^2lambda^2)/h^2`

B

`lambda_0=lambda`

C

`lambda_0=(2mclambda^2)/h`

D

`lambda_0=(2h)/(mc)`

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