Home
Class 11
PHYSICS
Preeti reached the metro station and fou...

Preeti reached the metro station and found that the escalator was not working . She walked up the stationary escalator in time `t_1` . On other days , if she remains stationary on the moving escalator takes her up in time `t_2`. The time taken by her to walk up on the moving escalator will be:

A

`(t_1t_2)/(t_2-t_1)`

B

`(t_1t_2)/(t_2+t1)`

C

`t_1-t_2`

D

`(t_1+t_2)/2`

Text Solution

Verified by Experts

Promotional Banner

Topper's Solved these Questions

  • GRAVITATION

    SARAS PUBLICATION|Exercise EXAMPLE|34 Videos
  • LAWS OF MOTION

    SARAS PUBLICATION|Exercise EXAMPLE|16 Videos

Similar Questions

Explore conceptually related problems

A person standing oin the floor of an elevator drops as coin. The coin reaches the floor of the elevator in a time t_1 if the elevator is stationary and in the t_2 if it is moving uniformly. Then

If N is the number of ways in which a person can walk up a stairway which has 7 steps if he can take 1 or 2 steps up the stairs at a time then the value of N//3 is _______.

A free ^238U nucleus kept in a train emits an alpha particle. When the train is stationary, a nucleus decays and a passenger measures that the separation between the alpha particle and the recoiling nucleus becomes x at time t after the decay. If the decay takes place while the train is moving at a uniform velocity v, the distance betwen the alpha particle and the recoiling nucleus at a time t after the decay as measured by the passenger is

Free ^238 U nuclei kept in a train emit alpha particles. When the train is stationary and a uranium nucleus decays, a passenger measures that the separation between the alpha particle and the recoiling nucleus becomes x in time t after the decay. If a decay takes place when the train is moving at a uniform speed v , the distance between the alpha particle and the recoiling nucleus at a time t after the decay, as measured by the passenger will be

Take a small stone. Hold it in your hand. We know that the force gravity due to the earth acts on each and every object. When we were holding the stone in our hand, the stone was experiencing this force, but it was balanced by a force that we were applying on it in the opposite direction. As a result, the stone remained at rest. Once we release the stone from our hands the only force that acts on it is the gravitational force of the earth and the stone falls down under its influence. Whenever an object moves under the influence of the force of gravity alone, it is said to be falling freely. Thus the released stone is in a free fall. In free fall, the initial velocity of the object is zero and goes on increasing due to acceleration due to gravity of the earth. During free fall, the frictional force due to air opposes the motion of the object and a buoyant force also acts on the object. Thus, true free fall is possible only in vacuum. For a freely falling object, the velocity on reaching the earth and the time taken for it can be calculated by using Newton's equations of motion. For free fall the initial velocity u=0 and the acceleration a=g . Thus, we can write the equations as v="gt",s=1/2"gt"^(2),v^(2)=2gs For calculating the motion of an object thrown upwards, acceleration is negative, i.e. in a direction opposite to the velocity and is taken to be -g. The magnitude of g is the same but the velocity of the object decreases due to -ve acceleration. The moon and the artificial satellites are moving only under the influence of the gravitational field of the earth. Thus they are in free fall. Which force acts on the stone in free fall after you release it?

Take a small stone. Hold it in your hand. We know that the force gravity due to the earth acts on each and every object. When we were holding the stone in our hand, the stone was experiencing this force, but it was balanced by a force that we were applying on it in the opposite direction. As a result, the stone remained at rest. Once we release the stone from our hands the only force that acts on it is the gravitational force of the earth and the stone falls down under its influence. Whenever an object moves under the influence of the force of gravity alone, it is said to be falling freely. Thus the released stone is in a free fall. In free fall, the initial velocity of the object is zero and goes on increasing due to acceleration due to gravity of the earth. During free fall, the frictional force due to air opposes the motion of the object and buoyant force also acts on the object. Thus, true free fall is possible only in vacuum. For a freely falling object, the velocity on reaching the earth and the time taken for it can be calculated by using Newton's equations of motion. For free fall the initial velocity u=0 and the acceleration a=g . Thus, we can write the equations as v="gt",s=1/2"gt"^(2),v^(2)=2gs For calculating the motion of an object thrown upwards, acceleration is negative, i.e. in a direction opposite to the velocity and is taken to be -g. The magnitude of g is the same but the velocity of the object decreases due to -ve acceleration. The moon and the artificial satellites are moving only under the influence of the gravitational field of the earth. Thus they are in free fall. What is the initial velocity and what is the effect of gravitational acceleration on the object in free fall?

A coin is dropped in a lift . It takes time t_(1) second to reach the floor when lift is stationary . It takes t_(2) second when the lift is moving up with constant acceleration . Then ,

A coin is dropped in a lift . It takes time t_(1) second to reach the floor when lift is stationary . It takes t_(2) second when the lift is moving up with constant acceleration . Then ,

A pendulum is suspended in a stationary lift and its time period is T. what will be its time period when the lift goes up with uniform velocity ?

A scooter starting from rest moves wilth as constant acceleration for a time /_\t_1 , then with a constant velocity for the next /_\t_2 and finally with a constant deceleration for the next /_\t_3 to come to rest. A 500N man sitting on the scooter behind the driver manages to stay at rest with respect to the scooter without touching any other part. The force exerted by the seat on the man is

SARAS PUBLICATION-KINEMATICS-EXAMPLE
  1. The distance travelled by a particle starting from rest and moving wit...

    Text Solution

    |

  2. A thin circular ring of mass M and radius R is rotating in a horizonta...

    Text Solution

    |

  3. A rectangular, a square, a circular and an elliptica loop, all in the ...

    Text Solution

    |

  4. Six vectors , a through f have the magnitude and directions indicat...

    Text Solution

    |

  5. The dimensions of (mu0 epsilon0)^(-1/2) are :

    Text Solution

    |

  6. The instantaneous angular position of a point on a rotating wheel is g...

    Text Solution

    |

  7. Two spheres A and B of masses m1 and m2 respectively collide . A is at...

    Text Solution

    |

  8. The velocity of a projectile at the initial point A is (2 hati +3 hatj...

    Text Solution

    |

  9. A stone falls freely under gravity . It covers distances h1 h2 and h3 ...

    Text Solution

    |

  10. A small object of uniform density rolls up a curved surface with an in...

    Text Solution

    |

  11. Vectors vecA, vecB and vec C are such that vecA.vecB =0 and vecA. vecC...

    Text Solution

    |

  12. The displacement ‘x’ (in meter)of a particle of mass ‘m’ (in kg) mo...

    Text Solution

    |

  13. A particle is moving such that its position coordinates (x,y) are (2m,...

    Text Solution

    |

  14. A balloon with mass m is descending down with an acceleration a (where...

    Text Solution

    |

  15. Point masses m1 and m2 are placed at the opposite ends of a rigid ro...

    Text Solution

    |

  16. What is the minimum velocity with a body of mass m must enter a vertic...

    Text Solution

    |

  17. If the magnitude of sum of two vectors is equal to the magnitude of di...

    Text Solution

    |

  18. Two cars P and Q starts from a point at the same time in a straight li...

    Text Solution

    |

  19. Preeti reached the metro station and found that the escalator was not ...

    Text Solution

    |

  20. The x and y coordination of the particle at any time are x=5t - 2t^2an...

    Text Solution

    |