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If vectors vecA=cos omegat hati+sin omeg...

If vectors `vecA`=`cos omegat hati+sin omegat hatj`and `vecB`=`cos (omegat)/2 hati+sin (omegat)/2 hatj` are function of time,then the value of t at which they are orthogonal to each other is:

A

t=0

B

`t=pi/(4omega)`

C

`t=pi/(2omega)`

D

`t=pi/omega`

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