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Let `f(x)` is a polynomial satisfying `f(x).f(y) = f(x) +f(y) + f(xy) - 2 ` for all `x, y` and `f(2) = 1025,` then the value of `lim_(x->2) f'(x)` is

A

`5.2^(8)`

B

`5.2^(9)`

C

`5.2^(7)`

D

`5.2^(10)`

Text Solution

Verified by Experts

The correct Answer is:
D

Given `f(x).f(y)= f(x) +f(y) +f(xy) -2`
Put `y=(1)/(x)`
`rArr {f(1)}^(2) =3f(1)-2`
`rArr {f(1)}^(2) -3f(1)+2=0`
`rArr (f(1)-1) (f(1)-2)=0`
`rArr f(1)=1,2`
`rArr f(1)=2, ( :' f(1) ne 1)`
`:.f(x).f((1)/(x))=f(x)+f((1)/(x))+2-2`
`rArr f(x).f((1)/(x))=f(x)+f((1)/(x))`
`rArr f(x)=1 pm x^(n)`
`:. f(2)=1 pm 2^(n)=1025`
`rArr 2^(n)=1024=2^(10)`
`rArr n=10`
`:.f(x)=1+x^(10)`
`rArr f'(x)=10x_(9)`
`:.lim_(x to 2) f'(x)=lim_(x to 2)10xx x^(9)=10xx2^(9)=5 xx 2^(10)`
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