Home
Class 9
MATHS
In a parallelogram ABCD, E and F are the...

In a parallelogram ABCD, E and F are the mid points of sides AB and CD respectively show that the line segments AF and EC trisect the diagonal BD

Text Solution

Verified by Experts

The correct Answer is:
Hence, AF and EC trisect the diagonal BD.
Promotional Banner

Topper's Solved these Questions

  • QUADRILATERALS

    SWAN PUBLICATION|Exercise Objective Type Questions|10 Videos
  • QUADRILATERALS

    SWAN PUBLICATION|Exercise Objective Type Questions ( Fill in the Blanks)|10 Videos
  • QUADRILATERALS

    SWAN PUBLICATION|Exercise Objective Type Questions ( Fill in the Blanks)|10 Videos
  • PROBABILITY

    SWAN PUBLICATION|Exercise OBJECTIVE TYPE QUESTIONS (FILL IN THE BLANKS)|6 Videos
  • STATISTICS

    SWAN PUBLICATION|Exercise Objective Type Questions (Fill in Blanks:) |1 Videos

Similar Questions

Explore conceptually related problems

In the fig ABCD is a parallelogram in which E and F are mid points of AB and CD respectively. Prove that the line segments CE and AF intersect diagonal BD

In a trapezium ABCD, if E and F be the mid points of the diagonals AC and BD respectively, then EF=

ABCD is a parallelogram . If P and Q are the mid-points of [BC] and [CD] respectively, show that vec AP + vec AQ=

In given Fig. , DeltaABC is isosceles with AB = AC. D, E, F are the mid-points of sides BC, AC and AB respectively. Show that the line segment AD is perpendicular to the line segment EF and is bisected by it.

In given Fig. , DeltaABC is isosceles with AB = AC. D, E, F are the mid-points of sides BC, AC and AB respectively. Show that the line segment AD is perpendicular to the line segment EF and is bisected by it.

E and F are the mid points of non-parallel sides AD and BC respectively of a trapezium prove that EF||AB.

ABCD is parallelogram. X and Y are the mid-points of BC and CD respectively. Prove that ar (DeltaAXY) =3/8 ar (||gm ABCD) .

If D,E and F are the mid-points of the sides BC,CA and AB, respectively of a DeltaABC and O is any point, show that (i) AD+BE+CF=0

ABCD is parallelogram. X and Y are the mid-points of BC and CD respectively. Prove that ar (DeltaAXY) =3/8 ar (||)^(gm) ABCD .

If D, E and F are three points on the sides BC, CA and AB, respectively, of a triangle ABC such that the lines AD, BE and CF are concurrent, then show that " "(BD)/(CD)*(CE)/(AE)*(AF)/(BF)=1