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In fig., triangleODC-triangleOBA, angleB...

In fig., `triangleODC-triangleOBA`, `angleBOC=125@0 ` and `angleCDO=70@0`. Find `angleDOC`, `angleDCO` and `angleOAB` .

Text Solution

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The correct Answer is:
`angleDOC = 55^(@), angleDCO = 55^(@)` and `angleOAB = 55^(@)`
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