In figure `triangleABE=triangleACD` show that `triangleADE~triangleABC` .
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CD and GH are respectively the bisectors of angleACB and angleEGF such that D and H lie on sides AB and FE of triangleABC and triangleEFG respectively. If triangleABC ~ triangleFEG , show that :- triangleDCB~triangleHGE .

CD and GH are respectively the bisectors of angleACB and angleEGF such that D and H lie on sides AB and FE of triangleABC and triangleEFG respectively. If triangleABC ~ triangleFEG , show that :- triangleDCA~triangleHGF .

triangleABC is an equilateral triangle angle BEC

ABCD is a tetrahedron such that each of the triangleABC , triangleABD and triangleACD has a right angle at A. If ar(triangleABC) = k_(1). Ar(triangleABD)= k_(2), ar(triangleBCD)=k_(3) then ar(triangleACD) is

In figure AB bot BC and DE bot AC. Prove that triangleABC ~ triangleAED .

In Fig., altitudes AD and CE of triangleABC intersect each other at the point P. Show that: (i) triangleAEP ~ triangleCDP (ii) triangleABD ~ triangleCBE (iii) triangleAEP ~ triangleADB (iv) trianglePDC ~ triangleBEC

Sides AB and BC and median AD of a triangle ABC are respectively proportional to sides PQ and QR and median PM of trianglePQR (see Fig.). Show that triangleABC ~ trianglePQR . .

E is a point on the side AD produced of a parallelogram ABCD and BE intersects CD at F. Show that triangleABE ~ triangleCFB .

In Fig., altitudes AD and CE of triangleABC intersect each other at the point P. Show that :- triangleAEP~triangleADB . .

In fig. D and E are points on side BC of triangleABC such that BD=CE and AD=AE. Show that triangleABDequivtriangleACE