Find `(dy)/(dx)` , if `x=a(costheta+thetasintheta)` , `y=a(sintheta-thetacostheta)`

If x and y are connected parametrically by the equations given, without eliminating the parameter, Find (dy)/(dx) . x=a(costheta+thetasintheta), y=a(sintheta-thetacostheta)

Find dy/dx of x=a(costheta+thetasintheta) , y=a(sintheta-thetacostheta)

If x=a(costheta+thetasintheta),y=a(sintheta-thetacostheta)," then "(dy)/(dx)=

Find (dy)/(dx) when : x=a(1+costheta),y=a(theta+sintheta) .

Find (dy)/(dx) , if x=costheta-cos2theta , y=sintheta-sin2theta

Find dy/dx , when: x=a(1-costheta),y=a(theta+sintheta)

Find (dy)/(dx) , if x=a(theta+sintheta), y=1(1-costheta) .

Find (dy)/(dx) , if x=a(theta+sintheta), y=1(1-costheta) .

Find (dy)/(dx) , if x=a(theta-sintheta) and y=a(1+cos theta)