`(-9)^2 = 81` . Is -9 a square root of 81?

Find whether each of the following numbers is a perfect square or not. 81

What will be the unit digit of the squares of the following numbers : 81

Find the square root of each of the following by the method of repeated subtraction: 81

If 0 lt= x lt= (pi)/(2) and 81^(sin^(2)x) + 81^(cos^(2)x) =30 then x is equal to :

Factorise : p^4 – 81

If the roots of the equaion x^4-12 x^3+c x^2+dx+81=0 are positive then the value of c is The value of d is. Roots of the equation 2cx+d=0 is

If 1,omega,omega^(2),...omega^(n-1) are n, nth roots of unity, find the value of (9-omega)(9-omega^(2))...(9-omega^(n-1)).

Number ending in 1, 4, 5, 6, 9 are not perfect squares.

Use the sign of >, -231+79+51 square -399+159+81