Home
Class 8
MATHS
Write a 3-digit bnumber abc as 100a+10b+...

Write a 3-digit bnumber abc as 100a+10b+c =99a+11b+(a-b+c)=11(9a+b)+(a-b+c)
If the number abc is divisible by 11,then what can yu say about (a-b+c)?
Is it necessary tht (a+c-b) should be divisible by 11 ?

Text Solution

Verified by Experts

The correct Answer is:
not necessary that (a-b+c) should be divisible by 11.
Promotional Banner

Topper's Solved these Questions

  • PLAYING WITH NUMBERS

    SWAN PUBLICATION|Exercise Exercise 1|10 Videos
  • PLAYING WITH NUMBERS

    SWAN PUBLICATION|Exercise Exercise 2|4 Videos
  • PLAYING WITH NUMBERS

    SWAN PUBLICATION|Exercise Do This |1 Videos
  • MENSURATION

    SWAN PUBLICATION|Exercise Exercise 11.4 |10 Videos
  • PRACTICAL GEOMETRY

    SWAN PUBLICATION|Exercise Try These |4 Videos

Similar Questions

Explore conceptually related problems

Write a 4-digit number abcd as 1000a+100b+10c+d=(1001a+99b+c)-(a-b+c-d) If the number abcd is divisible by 11,then what can you say about [(b+d)-(a+c)]?.

If a denotes the number of permutations of (x+2) things taken all at a time, b the number of permutations of x things taken 11 at a time and c the number of permutations of x-11 things taken all at a time such that a=182b c , find the value of xdot a) 10 b) 12 c) 15 d) 18

If a, b and c are distinct and D = |(a,b,c),(b,c,a),(c,a,b)|. then the square of the determinant of its cofactors is divisible by

In Delta ABC, (a + b+ c) (b + c -a) = kbc if

Let the three-digit numbers A28,3B9 and 62C, where A,B and C are integers between 0 and 9, be divisible by fixed integer K. Show that the determinant {:|(A,3,6),(8,9,C),(2,B,2)| is divisible by k.

The digits A,B,C are such that the three digit numbers A88, 6B8, 86 C are divisible by 72 the determinant |{:(A,6,8),(8,B,6),(8,8,C):}| is divisible by

The digits A,B,C are such that the three digit numbers A88, 6B8, 86 C are divisible by 72 the determinant |{:(A,6,8),(8,B,6),(8,8,C):}| is divisible by

If in triangle ABC, a, c and angle A are given and c sin A lt a lt c , then ( b_(1) and b_(2) are values of b)