Using expression `g=GM/(r^(2))` and knowing the value of G, calculate the value of the acceleration due to gravity. Take mass of the earth to be `6xx10^(24)` kg and its radius as `6.4xx10^(6)`m.

Explanation

The given expression is
`g=G M/(r^(2))`
Here `G=6.673xx10^(-11)Nm^(2)//kg^(2)`
M=mass of the earth
`=6xx10^(24)kg`
`r=` radius of earth
`=6.4xx10^(6)m`
`:.` From =n(1)we have
`g=(6.673xx10^(-11)xx6xx10^(24))/((6.4xx10^(6))^(2))=m//s^(2)`
`=9.77m//s^(2)`