Suppose you and your friend have mass 50 kg each. Suppose also that both of you are standing such that your centres of gravity are 1 m apart. Calculate the force of gravitation between you and your friend. Calculate also the force of gravity acting on you Equation `mg=G(mM)/(R^(2))`. Take the mass and radius of the earth as `6xx10^(24)` kg and `6.4xx10^(6)`m respectively.

Explanation

Here `m_(1)=50kg`
`m_(2)=50kg`
r=1m
`G=6.673xx10^(-11)Nm^(2)//kg^(2)`
F=?
Using `F=(Gm_(1)m_(2))/(r^(2))` we have
`F=(6.673xx10^(-11)xx50xx50)/((1)^(2))N`
`=1.668xx10^(-7)N`
Let force of gravity acting on me =F.
`:.F.=(GMm)/(R^(2))`
Here `G=6.673xx10^(-11)Nm^(2)//kg^(2)`
M=mass of earth
`=6.4xx10^(6)m`
`=6xx10^(24)kg`
m=50kg
R=radius of earth
`:.F.=(6.673xx10^(-11)xx6xx10^(24)xx50)/((6.4xx10^(6))^(2))N`
`=488.75` or 489 N