`CH_(3)-CH_(2)-Broverset("Dry "Ag_(2)O)to` Product of reaction is :

Options

A. `CH_(3)-CH_(2)-OH`
B. `H_(2)C=CH_(2)`
C. `CH_(3)-overset(O)overset(||)(C)-H`
D. `CH_(3)-CH_(2)-O-CH_(2)-CH_(3)`

Explanation

To solve the question regarding the reaction of bromoethane (CH₃CH₂Br) with dry silver oxide (Ag₂O), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants:**
- The reactant given is bromoethane (CH₃CH₂Br).
- The reagent used is dry silver oxide (Ag₂O).

2. **Understand the Reaction Type:**
- This reaction is an example of the Williamson ether synthesis, which typically involves the formation of ethers from alkyl halides and alkoxides.
- However, in this case, we are using dry Ag₂O, which will facilitate the formation of a symmetrical ether.

3. **Write the Reaction:**
- When bromoethane reacts with dry Ag₂O, the reaction can be represented as:
\[ 2 \, \text{CH}_3\text{CH}_2\text{Br} + \text{Ag}_2\text{O} \xrightarrow{\text{heat}} \text{CH}_3\text{CH}_2\text{OCH}_2\text{CH}_3 + 2 \, \text{AgBr} \]
- Here, the bromoethane undergoes a reaction to form diethyl ether (CH₃CH₂OCH₂CH₃) and silver bromide (AgBr).

4. **Identify the Product:**
- The product formed in this reaction is diethyl ether (CH₃CH₂OCH₂CH₃), which is a symmetrical ether.

5. **Conclusion:**
- The final product of the reaction between bromoethane and dry Ag₂O is diethyl ether.

### Final Answer:
The product of the reaction is diethyl ether (CH₃CH₂OCH₂CH₃).

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