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CH(3)underset(Br)underset(|)(C)HCH(3)ove...

`CH_(3)underset(Br)underset(|)(C)HCH_(3)overset("alc."//KOH)toAoverset(HBr//"peroxide")toBoverset(CH_(3)ONa)toC`
In the above reaction sequence, the final product is :

A

diethyl ether

B

1-methoxypropane

C

isopropyl alcohol

D

propylene glycol

Text Solution

AI Generated Solution

The correct Answer is:
To solve the given reaction sequence step by step, we will analyze each transformation and identify the final product. ### Step 1: Identify the starting compound The starting compound is: \[ \text{CH}_3\text{CHBrCH}_3 \] This is 2-bromopropane. ### Step 2: Reaction with alcoholic KOH When 2-bromopropane is treated with alcoholic KOH and heated, a dehydrohalogenation reaction occurs. This reaction involves the elimination of HBr, leading to the formation of an alkene. The reaction can be represented as: \[ \text{CH}_3\text{CHBrCH}_3 \xrightarrow{\text{alc. KOH, heat}} \text{CH}_3\text{CH}=\text{CH}_2 + \text{HBr} \] The product formed here is propene (CH₃CH=CH₂), which we will denote as compound A. ### Step 3: Reaction with HBr in the presence of peroxide Next, we treat the alkene (propene) with HBr in the presence of peroxide. According to the anti-Markovnikov's rule, the bromine will add to the less substituted carbon of the double bond. The reaction can be represented as: \[ \text{CH}_3\text{CH}=\text{CH}_2 + \text{HBr} \xrightarrow{\text{peroxide}} \text{CH}_3\text{CH}_2\text{CH}_2\text{Br} \] The product formed here is 1-bromopropane (CH₃CH₂CH₂Br), which we will denote as compound B. ### Step 4: Reaction with CH₃ONa Finally, we treat 1-bromopropane with sodium methoxide (CH₃ONa). This reaction is a nucleophilic substitution where the bromine is replaced by the methoxy group. The reaction can be represented as: \[ \text{CH}_3\text{CH}_2\text{CH}_2\text{Br} + \text{CH}_3\text{ONa} \rightarrow \text{CH}_3\text{CH}_2\text{CH}_2\text{OCH}_3 + \text{NaBr} \] The product formed here is 1-methoxypropane (CH₃CH₂CH₂OCH₃), which is our final product C. ### Final Answer The final product of the reaction sequence is: **1-methoxypropane (CH₃CH₂CH₂OCH₃)** ---

To solve the given reaction sequence step by step, we will analyze each transformation and identify the final product. ### Step 1: Identify the starting compound The starting compound is: \[ \text{CH}_3\text{CHBrCH}_3 \] This is 2-bromopropane. ### Step 2: Reaction with alcoholic KOH ...
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