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If the equation x^(2)-px+q=0 and x^(2)-a...

If the equation `x^(2)-px+q=0` and `x^(2)-ax+b=0` have a comon root and the other root of the second equation is the reciprocal of the other root of the first, then prove that `(q-b)^(2)=bq(p-a)^(2)`.

A

`aq(p-b)^(2)`

B

`bq(p-q)^(2)`

C

`bq(p-a)^(2)`

D

`aq(p-q)^(2)`

Text Solution

Verified by Experts

The correct Answer is:
C
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