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If c gt0 and 4a+clt2b then ax^(2)-bc+c=0...

If `c gt0` and `4a+clt2b` then `ax^(2)-bc+c=0` has a root in the interval

A

(2,4)

B

(0,1)

C

(0,2)

D

(-2,0)

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The correct Answer is:
C
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