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(x-ab)/(a+b) +(x-ac)/(a+c) +(x-bc)/(b+c)...

`(x-ab)/(a+b) +(x-ac)/(a+c) +(x-bc)/(b+c)=a+b+c`, then x=

A

`Sigma a`

B

`Sigma ab`

C

abc

D

none

Text Solution

Verified by Experts

The correct Answer is:
B
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