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(i)a xx (b + c) + b xx (c + a) + c xx(a...

`(i)a xx (b + c) + b xx (c + a) + c xx(a +b) =`

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To solve the given vector expression step by step, we will use the properties of the cross product. The expression we need to simplify is: \[ \mathbf{a} \times (\mathbf{b} + \mathbf{c}) + \mathbf{b} \times (\mathbf{c} + \mathbf{a}) + \mathbf{c} \times (\mathbf{a} + \mathbf{b}) \] ### Step 1: Expand the Cross Products Using the distributive property of the cross product, we can expand each term in the expression: \[ \mathbf{a} \times (\mathbf{b} + \mathbf{c}) = \mathbf{a} \times \mathbf{b} + \mathbf{a} \times \mathbf{c} \] \[ \mathbf{b} \times (\mathbf{c} + \mathbf{a}) = \mathbf{b} \times \mathbf{c} + \mathbf{b} \times \mathbf{a} \] \[ \mathbf{c} \times (\mathbf{a} + \mathbf{b}) = \mathbf{c} \times \mathbf{a} + \mathbf{c} \times \mathbf{b} \] ### Step 2: Combine All Terms Now, we can combine all the expanded terms together: \[ (\mathbf{a} \times \mathbf{b} + \mathbf{a} \times \mathbf{c}) + (\mathbf{b} \times \mathbf{c} + \mathbf{b} \times \mathbf{a}) + (\mathbf{c} \times \mathbf{a} + \mathbf{c} \times \mathbf{b}) \] This simplifies to: \[ \mathbf{a} \times \mathbf{b} + \mathbf{a} \times \mathbf{c} + \mathbf{b} \times \mathbf{c} + \mathbf{b} \times \mathbf{a} + \mathbf{c} \times \mathbf{a} + \mathbf{c} \times \mathbf{b} \] ### Step 3: Rearranging Terms We can rearrange the terms to group them by pairs: \[ \mathbf{a} \times \mathbf{b} + \mathbf{b} \times \mathbf{a} + \mathbf{a} \times \mathbf{c} + \mathbf{c} \times \mathbf{a} + \mathbf{b} \times \mathbf{c} + \mathbf{c} \times \mathbf{b} \] ### Step 4: Apply the Antisymmetry Property Using the property of the cross product that states \(\mathbf{x} \times \mathbf{y} = -(\mathbf{y} \times \mathbf{x})\), we can simplify: 1. \(\mathbf{b} \times \mathbf{a} = -(\mathbf{a} \times \mathbf{b})\) 2. \(\mathbf{c} \times \mathbf{a} = -(\mathbf{a} \times \mathbf{c})\) 3. \(\mathbf{c} \times \mathbf{b} = -(\mathbf{b} \times \mathbf{c})\) Substituting these into the expression gives: \[ \mathbf{a} \times \mathbf{b} - \mathbf{a} \times \mathbf{b} + \mathbf{a} \times \mathbf{c} - \mathbf{a} \times \mathbf{c} + \mathbf{b} \times \mathbf{c} - \mathbf{b} \times \mathbf{c} \] ### Step 5: Simplifying the Expression All terms cancel out: \[ 0 \] ### Final Result Thus, the final result of the expression is: \[ \boxed{0} \]
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  2. Projection of b = 2i + 3j -2k in the direction of vector a = i+2j+3k i...

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  3. (i)a xx (b + c) + b xx (c + a) + c xx(a +b) =

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  4. (i) If vecOA = a, vecOB = b, then the vector area of triangle OAB is ....

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  5. If the diagonals of a parallelogram are 3i+j-2k and i -3j +4k then its...

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  6. If a = 2i-3j+k, b=-i+k,c=2j-k then the area of parallelogram whose dia...

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  8. The distance of the point B(i+2j+3k) from the line which is passing th...

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  11. If [I, j, k] be a set of orthogonal unit vectors, then fill up the bla...

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  12. The components of a vector veca along and perpendicular to a non-zero ...

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  13. If r be any vector, then |r xx i|^(2) + |r xx j|^(2) + |r xxk|^(2) =...

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  14. The points O, A, B, C, D are such that vecOA = a, vecOB = b, vecOC = 2...

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