`a.b = 0 rArr`Vectors a and b are orthogonal (b)IF ABCD be a cyclic quadrilateral, then `A + C = (pi)/(2)` and `B + D = (pi)/(2)` (c )`[abc] =a.(bxxc)`. If `u = q-r, r-p, p-q and v = (1)/(a),(1)/(b),(1)/(c) ` and a,b,c are `T_(p),T_(q),T_(r)` of an HP, then the angle between the vectors u and v is .....
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The correct Answer is:
`theta = pi//2`
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